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-0.8=x-4.9x^2
We move all terms to the left:
-0.8-(x-4.9x^2)=0
We get rid of parentheses
4.9x^2-x-0.8=0
We add all the numbers together, and all the variables
4.9x^2-1x-0.8=0
a = 4.9; b = -1; c = -0.8;
Δ = b2-4ac
Δ = -12-4·4.9·(-0.8)
Δ = 16.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{16.68}}{2*4.9}=\frac{1-\sqrt{16.68}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{16.68}}{2*4.9}=\frac{1+\sqrt{16.68}}{9.8} $
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